Bootstrapping

Chapter 8 of Moderndive. Code for quiz 12.

Load the R packages we will use.

library(tidyverse)
library(moderndive)
library(infer)
library(fivethirtyeight)

What is the average age of members that have served in congress?

• Set random seed generator to 123

• Take a sample of 100 from the dataset congress_age and assign it to congress_age_100

set.seed(123)

congress_age_100 <- congress_age %>% 
  rep_sample_n(size = 100)

• congress_age is the population and congres_age_100 is the sample.

• 18,635 is the number of observations in the population and 100 is the number of observations in the sample.

---

Construct the confidence interval

1. Use specify to indicate the variable from congress_age_100 that you are interested in

congress_age_100 %>% 
  specify(response = age)

Response: age (numeric)
# A tibble: 100 x 1
     age
   <dbl>
 1  53.1
 2  54.9
 3  65.3
 4  60.1
 5  43.8
 6  57.9
 7  55.3
 8  46  
 9  42.1
10  37  
# ... with 90 more rows

---

2. generate 1000 replicates of your sample of 100

congress_age_100 %>% 
  specify(response = age) %>% 
  generate(reps = 1000, type = "bootstrap")

Response: age (numeric)
# A tibble: 100,000 x 2
# Groups:   replicate [1,000]
   replicate   age
       <int> <dbl>
 1         1  42.1
 2         1  71.2
 3         1  45.6
 4         1  39.6
 5         1  56.8
 6         1  71.6
 7         1  60.5
 8         1  56.4
 9         1  43.3
10         1  53.1
# ... with 99,990 more rows

The output has 100,000 rows.

---

3. calculate the mean for each replicate

• Assign the bootstrap_distribution_mean_age

• Display bootstrap_distribution_mean_age

bootstrap_distribution_mean_age <- congress_age_100 %>% 
  specify(response = age) %>% 
  generate(reps = 1000, type = "bootstrap") %>% 
  calculate(stat = "mean")

bootstrap_distribution_mean_age

Response: age (numeric)
# A tibble: 1,000 x 2
   replicate  stat
       <int> <dbl>
 1         1  53.6
 2         2  53.2
 3         3  52.8
 4         4  51.5
 5         5  53.0
 6         6  54.2
 7         7  52.0
 8         8  52.8
 9         9  53.8
10        10  52.4
# ... with 990 more rows

The bootstrap_distribution_mean_age has 1000 means.

---

4. visualize the bootstrap distribution

visualize(bootstrap_distribution_mean_age)

Calculate the 95% confidence interval using the percentile method

• Assign the output to congress_ci_percentile

• Display congress_ci_percentile

congress_ci_percentile <- bootstrap_distribution_mean_age %>% 
  get_confidence_interval(type = "percentile", level = 0.95)

congress_ci_percentile

# A tibble: 1 x 2
  lower_ci upper_ci
     <dbl>    <dbl>
1     51.5     55.2

Calculate the observed point estimate of the mean and assign it to obs_mean_age

• Display obs_mean_age

obs_mean_age <- congress_age_100 %>% 
  specify(response = age) %>% 
  calculate(stat = "mean") %>% 
  pull()

obs_mean_age

[1] 53.36

• Shade confidence interval

• Add a line at the observed mean, obs_mean_age, to your visualization and color it “hotpink”

visualize(bootstrap_distribution_mean_age) +
  shade_confidence_interval(endpoints = congress_ci_percentile) +
  geom_vline(xintercept = obs_mean_age, color = "hotpink", size = 1)

• Calculate the population mean to see if it is in the 95% confidence interval

• Assign the output to pop_mean_age

• Display pop_mean_age

pop_mean_age <- congress_age %>% 
  summarize(pop_mean = mean(age)) %>% pull()
  
pop_mean_age  

[1] 53.31373

• Add a line to the visualization at the population mean of pop_mean_age to the plot, color it “purple”

visualize(bootstrap_distribution_mean_age) +
  shade_confidence_interval(endpoints = congress_ci_percentile) +
  geom_vline(xintercept = obs_mean_age, color = "hotpink", size = 1) +
  geom_vline(xintercept = pop_mean_age, color = "purple", size = 3)

ggsave(filename = "preview.png", path = here::here("_posts", "2022-04-22-bootstrapping"))

• Is population mean the 95% confidence interval constructed using the bootstrap distribution?

  Yes

• Change set.seed (123) to set.seed(4346), rerun all the code.

  • When you change the seed is the population mean in the 95% confidence interval constructed using the bootstrap distribution?

  No

  • If you construct 100 95% confidence intervals approximately how many do you expect will contain the population mean?

  95